P27F5Gear Shift Lock Solenoid/Actuator A Stuck Off
- Generic OBD-II code · Powertrain
- How the car detects it
- With P27F5 the control unit concludes that shift lock actuator A remains in its passive state although it was told to act. Depending on the design, that can leave the lever free to leave Park without the brake, which defeats the brake interlock, or permanently blocked. No maker publishes this code. FCA recall 16V-249 describes a badly crimped harness terminal on the interlock solenoid of 2016 Jeep Grand Cherokee that cut solenoid function. Ford reports a shift lock actuator that misses its target position as P0929 and fixes it with a new module or software (SSM 51057). Typical culprits are a loose terminal, a weak coil or a broken return spring. P27F4 covers the actuator stuck in its active state; wiring faults are P0928 to P0931.
- What you may notice
- Selector leaves Park without the brake pedal being pressed
- Lever stays blocked in Park or Neutral
- Shift system warning message
- Likely causes
- LikelyLoose or badly crimped terminal at the lock solenoid
- PossibleWeak solenoid coil that no longer moves the lock pin
- RareBroken return spring or worn lock pin
- RareShifter module software misjudging the actuator position
- Repair
- Medium · Usually a job for a workshop.Typical cost: €80 – €900
- Related codes
Explanation from obdex (CC0), exactly as the app shows it. Guidance only; confirm with a workshop.