P0928Gear Shift Lock Solenoid/Actuator Control Circuit A/Open
- Generic OBD-II code · Powertrain
- How the car detects it
- The module that drives the shift lock (brake transmission shift interlock, BTSI) sees no continuity on control circuit A, so it cannot reliably release the selector from Park. FCA/Chrysler uses the code as P0928-00 BTSI Control: bulletin 08-072-14 (2013-14 Ram 1500, 2014 Durango with 8-speed) and 21-034-15 (2015 Chrysler 300 rotary shifter) name it when the selector will not leave Park or the knob turns without the brake applied; the cure there is a new electronic shifter. P0929 is the plausibility fault, P0930 and P0931 the low and high faults of circuit A, P092A the same open fault on circuit B. The driver usually cannot shift out of Park until the fault clears or the manual release is used.
- What you may notice
- Selector lever will not move out of Park even with the brake pressed
- Problem may disappear after the ignition is switched off and the modules go to sleep
- Rotary or electronic shifter can be moved without the brake applied
- Shift position flashes or a message asks to return the selector to Park
- Likely causes
- LikelyInternal fault in the electronic shifter module, often logged together with P0607 (documented by FCA)
- PossibleShift lock solenoid coil open
- PossibleBroken wire, poorly crimped or pushed-out terminal on the shift lock circuit
- Repair
- Medium · Usually a job for a workshop.Typical cost: €60 – €900
- Related codes
Explanation from obdex (CC0), exactly as the app shows it. Guidance only; confirm with a workshop.