P2888Park Lock/Pawl Actuator Circuit/Open
- Generic OBD-II code · Powertrain
- Turns on the check-engine light
- Can trigger limp mode
- How the car detects it
- P2888 flags an open circuit in the park lock actuator path: the output stage switches on but finds no load. Ford's 2024-25 OBD summary maps it, alongside P2887_13, for the 8F24, 8F35/8F40 and 8F57 front-drive automatics, and in the TR9070 dual-clutch gearbox as an open load on the parking lock hold solenoid, where it can also be reported as P2887_01. Typical findings are a broken wire or backed-out pin at the transmission connector, a burnt-out coil, or an internal break in the actuator. Depending on the design, the controller can then no longer hold or move the lock as commanded, so the car may stay in P, or the system refuses shift requests and keeps the lock applied for safety. CARB 13 CCR 1968.2 requires circuit continuity checks on electronic transmission outputs.
- What you may notice
- Vehicle stays in P or will not accept a gear
- Shift system warning
- Likely causes
- LikelyBroken wire or backed-out terminal at the actuator connector
- PossibleOpen coil in the park lock actuator or hold solenoid
- RareOutput stage in the control unit not switching
- Repair
- Hard · Usually a job for a workshop.Typical cost: €50 – €1,800
- Related codes
Explanation from obdex (CC0), exactly as the app shows it. Guidance only; confirm with a workshop.